Tomasz
I one of the previous conversations you had mentioned AB uses floats and that all integers upto 2^24 are represented accurately in floats. Is there a way around this issue (using mathematical tricks)? The following sum produces 268,460,128. The correct calculation is 268,460,113.
ic1 = 1; ic4 = 16; ic6 = 64; ic13 = 8192; ic14 = 16384; ic28 = 268435456; alliCs = ic1 + ic4 + ic6 + ic13 + ic14 + ic28; _TRACE("alliCs: " + NumToStr(alliCs, 1.0));
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Posted by: "TA" <tagroups@sbcglobal.net>
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